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陣列資料中的值, 如何透過replace轉換成另外一個值再塞回去陣列?

發表於 更新於 Disqus：

replace是在遇到字串會轉換為字串, 但是最後再塞回去變成新的值要怎麼做？

mdn 支援

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var str = 'Twas the night before Xmas...';
var newstr = str.replace(/xmas/i, 'Christmas');
console.log(newstr);  // Twas the night before Christmas...
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// 測式資料
let cityFilter = ['台北市', '臺北市', 950, '淡水區', '爲澎湖']

         function replaceStr(cityFilter){
             for (let i = 0; i < cityFilter.length; i++) {
                 if (cityFilter[i].includes("臺")) {
                     cityFilter[i].replace("臺", "台")
                     //return cityFilter[i].replace("臺", "台");   
// 這樣就變成只會替換一個單字, 而且是最先碰到的, replace就是單純替換字   
                     //return cityFilter                            
// 替換整個陣列並回傳替換的字
                 } else if (cityFilter[i].includes("950")) {
                     var numStr = cityFilter[i];
                     return numStr.replace("950", "台東市");
                 } else if (cityFilter[i].includes("淡水區")) {
                     var str2 = cityFilter[i]
                     return str2.replace("淡水區", "新北市")
                 } else if (cityFilter[i].includes("台南東")) {
                     var str3 = cityFilter[i]
                     return str3.replace("台南東", "台南市")
                 } else if(cityFilter[i].includes("偽澎湖")){
                     var str4 = cityFilter[i]
                     return str4.replace("為澎湖", "澎湖縣")
                 }
             }
         }